fizzbuzzっぽいの

3の倍数と3が含まれる数字のときに、(・∀・)vになります。

実装

>>> for i in range(1, 31):
...     if i % 3 == 0 or "3" in str(i):
...          print "(・∀・)v"
...     else:
...          print i
...

1
2
(・∀・)v
4
5
(・∀・)v
7
8
(・∀・)v
10
11
(・∀・)v
(・∀・)v
14
(・∀・)v
16
17
(・∀・)v
19
20
(・∀・)v
22
(・∀・)v
(・∀・)v
25
26
(・∀・)v
28
29
(・∀・)v

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